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x^2+x-30800=0
a = 1; b = 1; c = -30800;
Δ = b2-4ac
Δ = 12-4·1·(-30800)
Δ = 123201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{123201}=351$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-351}{2*1}=\frac{-352}{2} =-176 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+351}{2*1}=\frac{350}{2} =175 $
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